The number is three digits, the number is even, the tens digit is half the hundreds digit, the sum of the digit is 14 what is the number

Let x represent the digit in the hundreds place, y represent the digit in the tens place, and z represent the digit in the ones place. What do we know about each digit?

x: twice y (2, 4, 6, or 8)

y: half of x (1, 2, 3, or 4)

z: an even number (0, 2, 4, 6, or 8).

The sume of the digits is 14. So, x + y + z = 14

Choose one of the digits and look at your options (if any).

when x=2, then y = 1, which means z has to be 11 (NOT VALID)

when x=4, then y = 2, which means z has to be 8 (428 works!)

For fun, let's see if any other numbers work:

when x=6, then y = 3, which means z has to be 5 (NOT VALID)

when x=8, then y = 4, which means z has to be 2 (842 works!)

428 and 842 both work

can someone answer this question plz

step-by-step explanation:

the correct answers i think are b. and d.

give me brainliest if it is correct!