June has $1.95 in dimes and nickels. she has a total of 28 coins. how many of each type of coin does she have.

June has 17 nickels and 11 dimes

Let the number of dime coins = d

Let the number of nickel coins = n

The total number of coins = 28

n  +  d   =  28(1)

0.1d + 0.05n = 1.95(2)

Make n the subject of the formula in equation (1)

n  =  28  -  d(3)

Substitute equation (3) into equation (2)

0.1d  +  0.05(28 - d)  =  1.95

0.1d  +  1.4  -  0.05d  =  1.95

0.05d  =  1.95 - 1.4

0.05d = 0.55

d  =  0.55/0.05

d  =  11

Substitute d = 11 into equation (3)

n  =  28  - 11

n  =  17

June has 17 nickels and 11 dimes

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A dime = 0.10

A nickel = 0.05

N + D = 28 coins

Rewrite this as N = 28 -D

0.10D + 0.05N = 1.95

Replace N withe the rewritten equation above:

0.10D + 0.05(28-D) = 1.95

Use the Distributive Property:

0.10D + 1.4 - 0.05D = 1.94

Add the like terms:

0.05D + 1.4 = 1.95

Subtract 1.4 from both sides:

0.05D = 0.55

Divide both sides by 0.05

D = 0.55 / 0.05

D = 11

Nickels = 28 - 11 = 17

There are 11 dimes and 17 nickels.

answer: the answer is c.

step-by-step explanation:

she’s dividing 1/3 of the flour into 2 jars.

hope this : )

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0