Anticent math problem how many rabbitsand phesants 35 heads and 94 feet

If all were pheasants, there would be 35 pairs of feet. There are 47 pairs of feet, so there must be 47-35 = 12 rabbits. Each rabbit has one more pair of feet than a pheasant does.

There are 12 rabbits and 23 pheasants.

If you insist on equations, you can let p and r represent the numbers of pheasants and rabbits, then write ...

... p + r = 35

... 2p + 4r = 94

Divide the second equation by 2 and subtract the first:

... (2p +4r)/2 - (p +r) = (94)/2 - (35)

... r = 12 . . . . . . . . . . . simplify

... p + 12 = 35 . . . . . . use the value of r in the first equation

... p = 23 . . . . . . . . . . subtract 12

(p, r) = (23, 12)

range is infinite on both x and y axis positive and negative

step-by-step explanation: