1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the youngest?

Age difference between oldest the  youngest = 48 years

Step-by-step explanation:

Given: Ratio of ages of Kissi and Esinam is 3:5, ratios of ages of Esinam and Lariba is 3:5 and sum of the ages of all 3 is 147 years

To find: age difference between oldest the  youngest

Solution:

Let age of Lariba be x years

As ratios of ages of Esinam and Lariba is 3:5,

Age of Esinam =  years

As ratio of ages of Kissi and Esinam is 3:5,

Age of Kissi = years

Sum of the ages of all 3 = 147 years

Age of Lariba = x = 75 years

Age of Esinam =

Age of Kissi =

So,

Age difference between oldest the  youngest = 75 - 27 = 48 years

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15