In a certain country, the true probability of a baby being a boy is 0.514. among the next nine randomly selected births in the country, what is the probability that at least one of them is a girl?

The probability of a baby being a boy is 0.514.

Nine baby births are selected and we have to find the probability that at last one of them is a girl.

P(At least one out of 9 is baby girl) = 1 - P(No baby girl)

= 1 - P(All 9 are baby boy)

= 1 - (0.514)^9

= 1 - 0.0025

= 0.9975

The probability that at least one out of 9 selected births is baby girl is 0.9975

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

the answer is 45 i just did it on oddesy ware