Aright triangle is removed from a rectangle as shown in the figure. find the area of the remaining part of the rectangle. [area of a triangle = 1/2(b)(h)]

I found the same problem with its corresponding image.

The rectangle has a length of 8 inches and width of 6 inches.
The right triangle was taken from the width. Its short leg measures 2 inches and the remainder of the width was 2 inches.

Area of the rectangle = Length x Width
A = 8 inches * 6 inches
A = 48 square inches.

Area of a right triangle = 1/2 a h
a is the short leg = 2 inches
h is the long leg = width - remainder of the width = 6 in. - 2 in. = 4 inches.

Area = 1/2 * 2 in. * 4in.
Area = (1*2*4)/2
A = 8/2
A = 4 square inches.

Area of Rectangle - Area of Triangle = Area of remaining figure.

48 sq. in - 4 sq. in. = 44 sq. inches.

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )