Mathematics, 15.04.2021 23:10 babycakesmani
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The area of the rubber coating for a flat roof is 96 square feet. The
rectangular frame the carpenter built for the flat roof has dimensions such
that the length is 4 feet longer than the width. What are the dimensions
of the frame?
Answers: 2
Mathematics, 21.06.2019 16:30
Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
Answers: 2
Mathematics, 21.06.2019 19:10
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. release your mouse button when the item is place. if you change your mind, drag the item to the trashcan. click the trashcan to clear all your answers. solve this quadratic equation using the quadratic formula. 2x2 - 2x=1 need asap
Answers: 2
Mathematics, 21.06.2019 20:30
Daryl factors the polynomial p(x)=x3+x2−26x+24 to rewrite it as p(x)=(x+6)(x−4)(x−1). which equations must be true? there may be more than one correct answer. select all correct answers. p(1)=0 p(−4)=0 p(−1)=0 p(6)=0 p(4)=0 p(−6)=0
Answers: 1
Mathematics, 21.06.2019 22:00
You are standing next to a really big circular lake. you want to measure the diameter of the lake, but you don't want to have to swim across with a measuring tape! you decide to walk around the perimeter of the lake and measure its circumference, and find that it's 400\pi\text{ m}400? m. what is the diameter dd of the lake?
Answers: 3
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The area of the rubber coating for a flat roof is 96 square feet. The
rectan...
rectan...
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