Which value is an extraneous solution to the square root of 2x+3+6 = x x= -11 x= -3 x= 3 x= 11

Answer: x =  3 is extraneous======i assume this is your question:           we must get rid of the square root to solve this first. subtract 6 from both sides    square both sides of the equation. this is the step that produces extraneous solutions.    this is a quadratic equation; solve by making one side equal to zero and then see if it can be factored (or use quadratic equation, completing the square, etc.)    to factor, find two numbers that multiply to get 33 and sum to get -14.these two numbers are -11 and -3, so x² - 14x + 33 factors into (x-11)(x-3)    by the zero product property, the apparent solutions at x = 11, x = 3.but if we plug in x = 3 into the original equation to check:     we get a false statement. plugging in the other solution, x = 11, gives us    which is a true statement. therefore, x = 11 is the only solution; x = 3 is extraneous.

Is there a picture?