During the analysis, 0.00905 mol h2o is formed. calculate the amount of h atoms in 0.00905 mol h2o.

The amount of H atoms in 0.00905 mole H₂O is 1.09×10²² atoms

1 mole of H₂O = 2 moles of H

Therefore,

0.00905 mole H₂O = 0.00905 × 2

0.00905 mole H₂O = 0.0181 mole of H

From Avogadro's hypothesis,

1 mole of H = 6.02×10²³ atoms

Therefore,

0.0181 mole of H = 0.0181 × 6.02×10²³

0.0181 mole of H = 1.09×10²² atoms

Thus, 1.09×10²² atoms of H is present in 0.00905 mole H₂O

Learn more about Avogadro's number:

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