A non-cold-worked 1040 steel cylindrical rod has an initial length of 100 mm and initial diameter of 7.50 mm. is to be deformed using a tensile load of 18,000 N. It must not experience either plastic deformation or a diameter reduction of more than 1.5 x 10-2 mm. Would the 1040 steel be a possible candidate for this application

1040 steel will be a possible candidate for this application since : Yield strength > stress

Explanation:

The 1040 steel would  be a possible candidate for this application because the stress experienced by the load is Lesser than its Yield strength

Given that 1040 steel has the following parameter values

Modulus of elasticity ( GPa )  = 205

Yield strength ( Mpa ) =  450

Poisson's ratio = 0.27

limitation of = 1.5 x 10^-2 mm.

stress = Tensile load / area of steel

          = 18,000 N / 4.418 * 10^-5 m^2

          = 407 .424 Mpa

the equation above shows how temperature f, measured in degrees fahrenheit, relates to a temperature c, measured in degrees celsius. based on the equation, which of the following must be true?

a temperature increase of 1 degree fahrenheit is equivalent to a temperature increase of

5

9

degree celsius.

a temperature increase of 1 degree celsius is equivalent to a temperature increase of 1.8 degrees fahrenheit.

a temperature increase of

5

9

degree fahrenheit is equivalent to a temperature increase of 1 degree celsius.

a) i only

b) ii only

c) iii only

d) i and ii only

answer:

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explanation: