An object experiences an acceleration of 7.7 m/s^2. As a result, it accelerates from rest to 20 m/s. How much distance did it travel during that acceleration?

26m

Explanation:

Given parameters:

Acceleration = 7.7m/s²

Initial velocity = 0m/s

Final velocity  = 20m/s

Unknown:

Distance traveled  = ?

Solution:

To solve this problem, we use the expression below:

      v²   = u²   + 2aS

v is the final velocity

u is the initial velocity

a is the acceleration

S is the distance

            20²  = 0²   +  (2 x 7.7 x S)

            400  = 15.4S

              S = 26m

the ima (higher than 1m) will be greater than the ima with the height of 1m.