How to solve this question

Voltage across element X is 49.26 volts

Explanation:

The kirchhoff's voltage law states that the algebraic sum of voltages around a closed loop is equal to zero.

Applying the kirchhoff's voltage law in loop yields,

-160 + V₁ + V₂ + V₃ + Vₓ + 60 + V₄ = 0

-160 + 60 + V₁ + V₂ + V₃ + Vₓ + V₄ = 0

But we know that V = IR

-100 + IR₁ + IR₂ + IR₃ + IRₓ + IR₄ = 0

IR₁ + IR₂ + IR₃ + IRₓ + IR₄ = 100

I(R₁ + R₂ + R₃ + Rₓ + R₄) = 100

I = 100/(R₁ + R₂ + R₃ + Rₓ + R₄)

Substitute the given resistor values

I = 100/(18k + 20k + 45k + 100k + 20k)

I = 100/203k

I = 100/203×10³

I = 0.0004926 A

The voltage drop at element x is

Vₓ = IRₓ

Vₓ = 0.0004926*100×10³

Vₓ = 49.26 V

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