Print "Censored" if userInput contains the word "darn", else print userInput. End with a newline. Ex: If userInput is "That darn cat.", then output is: Censored Ex: If userInput is "Dang, that was scary!", then output is: Dang, that was scary! Note: If the submitted code has out-of-range access, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message. #include
#include
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
/* Your solution goes here */
return 0;
}

The program goes as follows

Comments are used to explain difficult lines

#include <iostream>

#include <string>

using namespace std;

int main()

{

string userinput;

getline(cin,userinput);

/* My Solution starts here*/

//Initialize sub string position to 0

int stringpos = 0;

// Declare an iterating variable to iterate through userinput

int startpos;  

//Declare and initialize a determinant variable

int k = 0;

while((startpos = userinput.find("darn",stringpos))!=string::npos)

{

 //If userinput contaings "darn", increase k by 1

k++;

// Go to next string position

stringpos = startpos+1;  

}

//If determinant variable k is p then, userinput does not contain "darn"

if(k==0)

{

 cout<<userinput;

}

//Otherwise, it contains "darn"

else

{

 cout<<"Censored";

}

/* My Solution ends here*/

return 0;

}

See attached for .cpp program file

the correct answer is "part of speech" if the portion used is "verb, noun" there is another question similar to this with the same question but different portion. the other portion is "hand write" and the correct component for that question is "antonym".

hope this . : )