Be sure to answer all parts. how would you prepare benzylamine (c6h5ch2nh2) from c6h5cooh? more than one step is required. qsleft1 edit structure qsright1 select the correct reagents for each step. x: nh3, nabh3cn h2, pd―c [1] lialh4, [2] h2o [1] socl2, [2] nh3 y: [1] (ch3)2culi, [2] h2o [1] lialh4, [2] h2o [1] dibal―h, [2] h2o [1] ch3mgbr, [2] h2o

Benzoic Acid is Converted into Benzyl Amine in following steps,

First the -OH group of Benzoic is replaced by -Cl by treating Benzoic acid with Thionyl Chloride.

The Benzoyl Chloride formed is treated with Ammonia, which replaces the -Cl of Benzoyl chloride with -NH₂ forming Benzamide.

Benzamaide on reduction by LiAlH₄ is converted to Benzyl Amine, as the strong reducing agent converts C=O (carbonyl) group into -CH₂- group.