How many moles of ions are in 285 ml of 0.0150 m mgcl2?

Answer : The number of moles of and ions are 0.00428 and 0.00856 moles respectively.

Explanation :

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

In this question, the solute is .

Given :

Volume of solution = 285 mL = 0.285 L    (1 L = 1000 mL)

Molarity = 0.0150 M

Now put all the given values in this formula, we get:

Thus, the number of moles of are 0.00428 moles.

By the stoichiometry we can say that, 1 moles of dissociates to give 1 mole of ion and 2 moles of ions.

So,

Number of moles of ion = 0.00428 mole

Number of moles of ion = 2 × 0.00428 = 0.00856 mole

Therefore, the number of moles of and ions are 0.00428 and 0.00856 moles respectively.

beta decay is the answer

a) the particles of the chair are strongly held together.