Chemistry, 23.07.2019 16:50 Richelleypinelley

Write a balanced equation of the combustion of cooking fat.

Answers: 2

Show answers

Answers

Answer from: princessmnicole2

Answer : Combustion reactions are those reactions which includes reacting with the oxygen along with the reactant.

Here, the reactant is cooking fat.

$C_{51}H_{88}O_{6} + 70 O_{2} --- 51 CO_{2} + 44 H_{2}O$

So when a long chain hydrocarbon which is cooking fat here reacts with oxygen the products obtained are carbon dioxide and water molecule.

One mole of fat reacts with 70 moles of oxygen and gives 51 moles of carbon dioxide and 44 moles of water molecule.

Answer from: jwood287375

The balanced equation for the combustion of cooking fat is

$\boxed{{{\text{C}}_{51}}{{\text{H}}_{88}}{{\text{O}}_6}+70{{\text{O}}_2}\to51{\text{C}}{{\text{O}}_{\text{2}}} + 44{{\text{H}}_{\text{2}}}{\text{O}}}$ .

Further explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Combustion reaction:

It is the reaction in which the reactant reacts with molecular oxygen to form carbon dioxide and a water molecule. Molecular oxygen acts as the oxidizing agent in these reactions. A large amount of heat is released and therefore combustion reactions are exothermic in nature.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the combustion reaction, ${{\text{C}}_{51}}{{\text{H}}_{88}}{{\text{O}}_6}$ reacts with ${{\text{O}}_2}$ to form ${\text{C}}{{\text{O}}_{\text{2}}}$ and ${{\text{H}}_{\text{2}}}{\text{O}}$ . The physical state of ${{\text{C}}_{51}}{{\text{H}}_{88}}{{\text{O}}_6}$ is liquid, ${{\text{O}}_2}$ is gas, ${\text{C}}{{\text{O}}_{\text{2}}}$ is gas and ${{\text{H}}_{\text{2}}}{\text{O}}$ is gas. The unbalanced chemical equation is as follows:

${{\text{C}}_{51}}{{\text{H}}_{88}}{{\text{O}}_6}\left( l \right)+{{\text{O}}_2}\left( g \right)\to{\text{C}}{{\text{O}}_{\text{2}}}\left( g \right)+{{\text{H}}_{\text{2}}}{\text{O}}\left( g \right)$

Step2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

⦁On reactant side,

Number of carbon atoms is 51.

Number of hydrogen atoms is 88.

Number of oxygen atoms is 6.

⦁On product side,

Number of carbon atoms is 1.

Number of hydrogen atoms is 2.

Number of oxygen atoms is 3.

Step3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side but in the combustion reaction there is only carbon, hydrogen, and oxygen atom.

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms.

To balance the number of atoms we have to multiply ${{\text{O}}_2}$ by 70, ${\text{C}}{{\text{O}}_{\text{2}}}$ by 51 and ${{\text{H}}_{\text{2}}}{\text{O}}$ by 44. This gives,

${{\text{C}}_{51}}{{\text{H}}_{88}}{{\text{O}}_6}+\boxed{70}{\text{ }}{{\text{O}}_2} \to \boxed{51}{\text{ C}}{{\text{O}}_{\text{2}}}+\boxed{44}{\text{ }}{{\text{H}}_{\text{2}}}{\text{O}}$

Step 5: So the balanced chemical equation is given as follows:

${{\text{C}}_{51}}{{\text{H}}_{88}}{{\text{O}}_6}+70{{\text{O}}_2}\to51{\text{C}}{{\text{O}}_{\text{2}}}+44{{\text{H}}_{\text{2}}}{\text{O}}$

Learn more:

1. Balanced chemical equation:

2. Identify the precipitate in the reaction:

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: cooking fat, combustion, oxygen, carbon, hydrogen, CO2, H2O, O2, C51H88O6, 70 O2, 51 CO2, 44 H2O, reactant side, product side, liquid, gas.

Answer from: Quest

Talc (french chalk) is the ingredient

Answer from: Quest

ugh fiel iente of insistí is did kiwis jaj

Another question on Chemistry

Chemistry, 21.06.2019 23:00

50 pts plz what is the physical state of matter of baking soda.

Answers: 1

Answer

Chemistry, 22.06.2019 09:00

Chemical energy is a form of a. kinetic energy only. b. both potential and kinetic energy. c. neither potential nor kinetic energy. d. potential energy only. reset

Answers: 1

Answer

Chemistry, 22.06.2019 10:10

For the reaction, 4 a(g) + 3 b(g) => 2 c(g), the following data were obtained at constant temperature. experiment initial[a],mol/l initial [b],mol/l initial rate,m/min 1 0.200 0.150 5.00 2 0.400 0.150 10.0 3 0.200 0.300 10.0 4 0.400 0.300 20.0 which of the following is the correct rate law for the reaction? 1. rate = k[a]2[b]2 2. rate = k[a][b] 3. rate = k[a]2[b] 4. rate = k[a][b]2

Answers: 3

Answer

Chemistry, 22.06.2019 11:00

Predict the products of the following acid-base reactions, and predict whether the equilibrium lies to the left or to the right of the reaction arrow.part ao2-(aq)+h2o(l)< => express your answer as part of a chemical equation. identify all of the phases in your answer.o2-(aq)+h2o(l) < => oh-(aq)+oh-(aq)part bpredict whether the equilibrium lies to the left or to the right of the equation in previous part.h2o is a stronger acid than oh–, so the equilibrium lies to the right.h2o is a weaker acid than oh–, so the equilibrium lies to the left.h2o is a stronger acid than oh–, so the equilibrium lies to the left.h2o is a weaker acid than oh–, so the equilibrium lies to the right.part cch3cooh(aq)+hs? (aq) < => express your answer as part of a chemical equation. identify all of the phases in your answer.ch3cooh(aq)+hs-(aq) < => h2s(aq)+c2h3o2-(aq)h2s(aq)+c2h3o2-(aq)part dpredict whether the equilibrium lies to the left or to the right of the equation in previous part.ch3cooh is a weaker acid than h2s, so the equilibrium lies to the right.ch3cooh is a weaker acid than h2s, so the equilibrium lies to the left.ch3cooh is a stronger acid than h2s, so the equilibrium lies to the right.ch3cooh is a stronger acid than h2s, so the equilibrium lies to the left.part eno2-(aq)+h2o(l) < => express your answer as part of a chemical equation. identify all of the phases in your answer.no2-(aq)+h2o(l) < => part fpredict whether the equilibrium lies to the left or to the right of the equation in previous part.hno2 is a stronger acid than h2o, so the equilibrium lies to the right.hno2 is a weaker acid than h2o, so the equilibrium lies to the left.hno2 is a stronger acid than h2o, so the equilibrium lies to the left.hno2 is a weaker acid than h2o, so the equilibrium lies to the right.

Answers: 1

Answer

You know the right answer?

Write a balanced equation of the combustion of cooking fat....

Questions