Chemistry, 16.07.2019 14:30 jennifer2129

For each of the given elements, list two other elements that have similar chemical properties. a. iodine b. barium c. iron

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Answer from: karicloou1332

For A: The elements having similar chemical properties as of iodine are fluorine and bromine.

For B: The elements having similar chemical properties as of barium are magnesium and calcium

For C: The elements having similar chemical properties as of iron are ruthenium and osmium.

Explanation:

In a periodic table, elements are arranged in 18 vertical columns known as groups and 7 horizontal rows known as periods.

Elements arranged in a group show similar chemical properties because of the presence of same number of valence electrons.

For A: Iodine

Iodine is present in Group 17 of the periodic table. The elements present in this group are Fluorine, Chlorine, Bromine, Iodine and Astatine.

The elements having similar chemical properties as of iodine are fluorine and bromine.

For B: Barium

Barium is present in Group 2 of the periodic table. The elements present in this group are Beryllium, Magnesium, Calcium, Strontium, Barium and Radium.

The elements having similar chemical properties as of barium are magnesium and calcium

For C: Iron

Iron is present in Group 8 of the periodic table. The elements present in this group are Iron, Ruthenium, Osmium and Hassium.

The elements having similar chemical properties as of iron are ruthenium and osmium.

Answer from: Quest

8.7 degrees celsius and 15.6 degrees fahrenheit
This is an environmental science question. what are the average annual temperatures of alice spring

This is an environmental science question. what are the average annual temperatures of alice spring

Answer from: Quest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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