An irregularly shaped stone was lowered into a graduated cylinder holding a volume of water equal to 2.0 ml. The height of the water rose to 7.0 ml. If the mas of the stone was 25 g, what is the density?

The density of the stone whose mass is 25 g and its volume is 5 mL is 5 g/mL.

We have a graduated cylinder holding a volume of water equal to 2 mL. After a stone is added, the height of the water rose to 7 mL. The volume of the stone is equal to the difference in the levels of water.

The stone has a volume of 5 mL and a mass of 25 g. Its density, that is the ratio of the mass to the volume, is:

The density of the stone whose mass is 25 g and its volume is 5 mL is 5 g/mL.The density of the stone is 5 g/cm³.

Mass = 25 g

Volume = 7 mL – 2 mL = 5 mL = 5 cm³

Density = mass/volume = 25 g/5 cm³ = 5 g/cm³

Explanation:

1.solid

2.carbon dioxide

3.helium