Mercury poisoning is a debilitating disease that is often fatal. In the human body, mercury reacts with essential enzymes leading to irreversible inactivity of these enzymes. If the amount of mercury in a polluted lake is 0.4 Hg/mL, what is the total mass in kilograms of mercury in the lake

The total mass of mercury in the lake is 631,542.7 kg

Explanation:

Question: The given dimensions of the lake as obtained from a similar question posted online are;

The surface area of the lake, A = 100 mi²

The lake's average depth, d = 20 ft.

The concentration of the mercury, C = 0.4 μg Hg/mL = 0.4 × 10⁻⁶ kg Hg/L

Therefore, we have;

The volume of water mixture in the lake, V = A × d

∴ V = 100 mi² × 20 ft. = 2,787,840,000 ft.² × 20 ft. = 55,756,800,000 ft.³

1 ft³ = 28.31685 L

∴ 55,756,800,000 ft.³ = 55,756,800,000 ft.³ × 28.31685 L/ft.³ = 1.57885675 × 10¹² L

The total mass of mercury in the lake, m = C × V

∴ m = 0.4 × 10⁻⁶ kg Hg/L × 1.57885675 × 10¹² L = 631,542.7 kg

The total mass of mercury in the lake, m = 631,542.7 kg.

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explanation:

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the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be