How many moles are in 175g
(Ca(NO3)2

appx. 1.07 moles

Explanation:

175g of molecule Ca(NO3)2

To find the # of moles, use stoichoimetry.

1. We need the molar mass of Ca(NO3)2.

Ca mass: 40.08 g

NO3 mass: N + 3(O) --> 14.01 + 3(16.00) --> 62.01

Molar mass = Ca + 2(NO3) --> 40.08 + 2(62.01) --> 164.1 g

2. write out the calculation

175g Ca(NO3)2 * (1 mole Ca(NO3)2)/(molar mass of Ca(NO3)2)

175 g Ca(NO3)2 * (1 mole Ca(NO3)2)/(164.1 g Ca(NO3)2)

The g units cancel out and we're left with moles.

Simply perform the calculation now: 175*1/164.1 ≅1.07 moles

b.

the accuracy of the data.