container has 3 moles of gas with a volume of 60 liters and at a temperature of 250 K, Calculate the pressure inside the container in kPa

103.9 KPa

Explanation:

From the ideal gas equation;

PV=nRT

From the parameters given;

P= ?

T=250 K

V= 60L

n=3

R=0.082 atmLK-1mol-1

P= nRT/V

P= 3 × 0.082 × 250/60

P= 1.025 atm

1 atm=101325 pascals

1.025 atm = 1.025 atm × 101325 pascals/1atm

= 103.9 KPa

103.9kPa

Explanation:

To solve this question we must use the equation:

PV = nRT

P = nRT / V

Where P is pressure in atm

n are moles of the gas = 3mol

R is gas constant = 0.082atmL/molK

T is absolute temperature = 250K

V = 60L

P = 3mol*0.082atmL/molK*250K / 60L

P = 1.025atm

As 1atm = 101.325kPa

1.025atm * (101.325kPa / 1atm) = 103.9kPa

fire could start, buildings collapsing, and ash falling from the sky.

explanation:

this is because the buildings or plants could catch on fire and the buildings would most likely collapse. lastly ash would fall because all the burning would cause ash to fall from the sky.

hope this .

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.