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1. 3.83 L

2. 0.368 mole

Explanation:

1. Determination of the volume

Pressure (P) = 3.21 atm

Temperature (T) = 202 K

Number of mole (n) = 0.741 mole

Gas constant (R) = 0.0821 L.atm/molK

Volume (V) =?

The volume can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

3.21 × V = 0.741 × 0.0821 × 202

3.21 × V = 12.3497283

Divide both side by 3.21

V = 12.2888922 / 3.21

V = 3.83 L

Thus, the volume of the gas is 3.83 L

2. Determination of the number of mole.

Pressure (P) = 2.50 atm

Temperature (T) = 215 K

Volume (V) = 2.60 L

Gas constant (R) = 0.0821 L.atm/molK

Number of mole (n) =?

The number of mole can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

2.50 × 2.60 = n × 0.0821 × 215

6.5 = n × 17.6515

Divide both side by 17.6515

n = 6.5 / 17.6515

n = 0.368 mole

Thus, the number of mole of the gas is 0.368 mole.

the answers would be

the first one and the second one