Thank u! :) Using the equation E°cell = E°cathode - E°anode, calculate the overall cell potential for the cell in step b. (Step b- fill in the blanks for the drawing of a voltaic cell that’s made with copper/copper (II) nitrate (E° = 0.34 V) and zinc/zinc (II) nitrate (E°= -0.76 V). Be sure to show all steps completed to arrive at the answer.

They are all full and don't need any more electrons in there outer shell.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Bthats what im doing to and i figured it out it is b