Ammonia nh3 chemically reacts with oxygen gas o2 to produce nitric oxide no and water h2o . what mass of water is produced by the reaction of 8.45g of oxygen gas? round your answer to 3 significant digits.

1) Balanced chemical reaction

4NH3 + 5O2 ---> 4NO + 6H2O

2) Molar ratios

4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O

3) Convert 8.45 g of O2 to moles

moles = mass in grams / molar mass = 8.45 g / 32.0 g/mol = 0.264 mol O2

4) Proportion

5 mol O2 / 6 mol H2O = 0.264 mol O2 / x

=> x = 0.264 mol O2 * 6 mol H2O / 5 mol O2 = 0.3168 mol H2O

5) Convert 0.3168 mol H2O in grams

mass = molar mass * number of moles

molar mass H2O = 18.0 g/mol

mass = 18.0 g/mol * 0.3168 mol = 5.7024 g ≈ 5.70 g

5.70 g

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.