Aballoon contains 5.5 l of air at 303 k and 101.3 kpa. after an hour, the air inside the balloon cools to 297 k. what is the final volume of the air in the balloon, assuming that it is an ideal gas and that the pressure does not change?

Final Volume = 5.39L

Explanation:

Parameters given:

Initial Volume (V1) = 5.5L

Initial Temperature (T1) = 303K

Initial Pressure = 101.3 kPa

Final Temperature (T2) = 297K

Final Volume (V2) = ?

Pressure is constant

The formular relating these parameters is Charles law. Charles's Law states that the Volume (V) of a gas is directly proportional to the temperature (T). This law is valid as long as the pressure and the amount of gas remains constant.

V1 / T1 = V2 / T2

making V2 subject of interest,

V2 = (T2 * V1) / T1

V2 = (297 * 5.5 ) / 303

V2 = 5.39L

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answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

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~ trueboss72