Which aqueous solution has the lowest boiling point?
a.0.20 m (nh4)2s
b. 0.20 m fei3
c. 0.20 m k2so4
d. 0.20 m c2h5oh

- D. 0.20 m

Explanations:- When a on volatile solute is added to a solvent then the boiling point of the solution increases(elevated) and we call it elevation in boiling point.

Elevation in boiling point is directly proportional to the molality of the solution and the Van't Hoff factor "i" which is the number of ions we get on dissociation.

The equation is written as:

where is the boiling point elevation constant.

We have all the aqueous solutions, so the boiling point elevation constant value will remain same for all of them. The molality for all the solutions is also same. So, elevation in boiling point will depend only on the value of Van't Hoff factor.

Lower is the value of "i", lower will be the boiling point and vice versa.

The question asks, which aqueous solution has the lowest boiling point. So, we nede to choose the one with the lowest value of "i".

i = 3

i = 4

i = 3

is a covalent molecule and so it does not dissociate to give the ions and hence the value of "i" for this is 1.

Comparing the "i" values for all the solutions, the least value is for ethyl alcohol means the boiling point of 0.20 m ethyl alcohol solution will be lowest.

So, the correct answer is D. 0.20 m .

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.