7. HgO(s) + H,0 =Hg1,2- + 2 OH Consider the equilibrium above. Which of the following changes will increase the
concentration of Hg1,2- ?
a. Increasing the concentration of OH-
b. Adding 6 M HNO3
c. Increasing the mass of HgO present
d. Increasing the temperature
e. Adding a catalyst

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i believe the answer is a.

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

the maximum mass of nh3 is nh3 in grams