Given the following info about a 1L solution determine the final pH of the buffer after the addition of strong acid. Initial HAc = 0.71

Initial pH = 5.12

Ka = 1.8x10-5

To the buffer was added 0.068 moles of HCl.

-1*log((1.8*10^-5*(X-Z)/(1.8*10^-5* X/(10^-Y)+Z)))

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Why doesn't heat added to water make the tempature rise above 100c

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