Use the balanced equation from #13 to answer the following: Calculate how many moles of SO2 can be produced with when given 75 grams of CS2.

Now calculate how many moles of SO2 can be produced with when given 96 grams of O2.

Which one is the limiting reactant (75 grams of CS2 or 96 grams of O2)? How do you know?

1. 9600 moles

2. 4096 moles

Explanation:

CS2 + 3 O2=> CO2 + 2 SO2

1. The ratio for CS2: SO2 is :

1:2

If there are 75g of CS2 then there are:

75 × 2= 150g of SO2

Moles = mass × Mr

Moles = 150 × 64

Moles = 9600

2. The ratio for O2 : SO2 is:

3:2

If there are 96g of O2 then there are:

96 × 2/3 = 64g of SO2

moles = mass × Mr

Moles = 64 × 64

Moles = 4096

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Explanation:

answer: your mm

explanation:

i would say b

explanation:

but i think i would need more information than that