_N2 + _H2 = _NH3
Will there be any leftover reactants left?
(Kinda urgent)

This reaction is the synthesis of Ammonia using Nitrogen and Hydrogen gas.

N+H→NH3

We must remember that Nitrogen and Hydrogen are both diatomic molecules in their standard gas form. This adjusts the equation to

N2+H2→NH3

Now we need to adjust coefficients in order to balance the atoms on each side of the equation. Currently, we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

We can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

N2+3H2→2NH3

This gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.

Explanation:

I hope this was helpful.

SMARTERTEACHER

Balance the equation N2 + H2 ⇒ NH3

Balancing chemical equations is usually easier than it looks

There are 2 Nitrogens and 2 Hydrogens on the left side

There are 1 Nitrogen and 3 Hydrogens on the right side

Hydrogen seems to be the more complicated term so we should start with that

_N2 + _H2 ⇒ _NH3

With 2 H on one side and 3 on the other, our common multiple is 6

To balance the H we need to multiply H2 by 3 and NH3 by 2

_N2 + 3H2 ⇒ 2NH3

Now that we have H balanced, we need to look at N

There are 2 Nitrogens on both sides of the equation, so in this case, it is done

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