What is the energy of light with a wavelength of 468 nm? (The speed of light
in a vacuum is 3.00 x 10^8m/s, and Planck's constant is 6.626 x 10^-34J·s.)
A. 2.35 x 10^27J
B. 4.25 x 10^-28mJ
C. 2.35 x 10^18J
D. 4.25 x 10^-19J

The answer for the problem is explained below.

The option for the answer is "D".

Therefore the energy of the light is  4.25 × 10^-19 J

Explanation:

Given:

wavelength (λ) = 468 nm = 468×10^-9 m

speed of light (c) = 3.00 x 10^8m/s

Planck's constant is 6.626 x 10^-34J·s

To solve:

energy of light (E)

We know,

E =(h×c) ÷ λ

E = ( 6.626 x 10^-34 ×  3.00 x 10^8) ÷ 468×10^-9

E = 4.25 × 10^-19 J

Therefore the energy of the light is  4.25 × 10^-19 J

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