Suppose "Element X" has a molar mass of 38.5 g/mol. How many atoms of Element X would be present in 2.78 mol?

16.74×10²³ atoms

Explanation:

Given data:

Number of moles of X = 2.78 mol

Number of atoms = ?

Solution:

According to Avogadro number.

1 mole of any substance contain 6.022×10²³ atoms. Thus,

2.78 mol × 6.022×10²³ atoms / 1 mol

16.74×10²³ atoms

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

i believe the answer is a.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.