You complete titration of 15.0ml of unknown acid with 14.16ml of 1.25 M NaOH. What’s the molar it’s of the unknown acid? Assume the acid is monoprotic 1 mole of acid reacts with 1 mole of base.

The molarity of the unknown acid : 1.18 M

Titration is a procedure for determining the concentration of a solution by reacting with another solution that is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titration formula

M₁V₁n₁=M₂V₂n₂

monoprotic acid⇒n₁=1

NaOH monoprotic base⇒n₂=1

n+h→nh3

we must remember that nitrogen and hydrogen are both diatomic molecules in their standard gas form. this adjusts the equation to

n2+h2→nh3

now we need to adjust coefficients in order to balance the atoms on each side of the equation. currently we have 2 atoms of nitrogen and 2 atoms of hydrogen on the reactant side and 1 atom of nitrogen and 3 atoms of hydrogen on the product side.

we can balance the hydrogens by placing a coefficient of 2 in front of ammonia and a coefficient of 3 in front of the hydrogen.

n2+3h2→2nh3

this gives us 6 hydrogen on each side and coincidentally the nitrogens now equal 2 on each side.