At STP, 32 grams of O2 would occupy the same volume as:

At STP 32 g of O₂ would occupy by the same volume as  4 g of He

Complete question

At STP 32 g of O₂ would occupy by the same volume as:

Standard Conditions

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So the gas will have the same volume if the number of moles is the same

mol of 32 grams of O₂ :

So mol of 4 g He = mol of 32 g O₂