A sample of nitrogen gas with a volume of 180 cm at a temperature of 27°C and a pressure of 101 kNm-2 is allowed to expand to a volume of
220 cm. What is its final pressure?

The final pressure of gas is 82.64 KNm⁻²

Explanation:

Given data:

Initial volume of gas = 180 cm³

Temperature of gas = 27°C

Initial pressure = 101 KNm⁻²

Final volume = 220 cm³

Final pressure = ?

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

101 KNm⁻² × 180 cm³ = P₂ × 220 cm³

P₂ = 18180 KNm⁻². cm³/220 cm³

P₂ = 82.64 KNm⁻²

The final pressure of gas is 82.64 KNm⁻².

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.