Question 4 of 10
2 Points
A ball is dropped from a height of 12 feet and returns to a height that is one-
half of the height from which it fell. The ball continues to bounce half the
height of the previous bounce each time. How far will the ball have traveled
vertically when it hits the ground for the fifth time? It might be helpful to
sketch the path of the ball.
O
A. 1.5 feet
O
O
O
B. 34.5 feet
c. 24 feet
D. 12 feet

The ball bounces half as high each time right? First he shows that the sum of the distance traveled is: 10m - the original height of the ball, plus 10(1/2)m + ...

Step-by-step explanation:

The ball bounces half as high each time right? First he shows that the sum of the distance traveled is: 10m - the original height of the ball, plus 10(1/2)m + ...

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3