1. Working in the laboratory, a student find the density of a piece of pure aluminum to be 2.85 g'om? The accepted value for the density of aluminum is 2.699 g/cm? What is the student's
percent error?

5.59 %

Explanation:

From the question given above, the following data were obtained:

Observed value of density = 2.85 g/cm³

True value of density = 2.699 g/cm³

Percentage error =.?

The percentage error of the student can be obtained as follow:

Percentage error = |Observed value – True value|/True value × 100

Percentage error = |2.85 – 2.699|/2.699

Percentage error = 0.151/2.699 × 100

Percentage error = 5.59 %

Therefore, the percentage error of the student is 5.59 %.

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