Compute the permutations and combinations. a farmer buys 2 cows, 3 pigs, and 10 sheep from a seller who has 7 cows, 4 pigs, and 10 sheep. how many choices of animals does he have? 845426

Farmer has 7 choice for cow out of which he choose only 2

4 choice for pig and he choose only 3 pigs

10 choice for sheep and he choose all 10 sheep

Number of ways of choosing cows = 7C2

Number of ways of choosing pigs = 4C3

number of ways of choosing sheep = 10C 10

all these three groups of different animals can make different groups when taken together

That is : 7C2 * 4C3 * 10C10 = 21 * 4 * 1 = 84 ways

Answer : 84

step-by-step explanation: noo

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.