Which of the following substances is more likely to dissolve in water? Which of the following substances is more likely to dissolve in water? HOCH2CH2OH O || CH3(CH2)9CH CCl4 CHCl3 CH3(CH2)8CH2OH

The compound HOCH2CH2OH having two O - H groups is more likely to interact with water.

A substance is soluble in water if it is capable of interacting in an electrostatic interaction. Water can form hydrogen bonds with other molecules that posses polar O - H bonds.

Hence, looking at the options provided in the question, we will observe that the compound HOCH2CH2OH having two O - H groups is more likely to interact with water.

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HOCH₂CH₂OH

Explanation:

You generally assume that polar dissolves polar and nonpolar dissolves nonpolar.  Since water is polar, we are looking for a polar molecular.  

This cancels out CH₃(CH₂)₉CH and CCl₄.

You are left with CHCl₃, CH₃(CH₂)₈CH₂OH, and HOCH₂CH₂OH.  You would pick the third option since it is the most polar.

sodium (na), for example, has one electron in its valence shell. this is an unstable state because that valence shell needs eight electrons to be full. in order to fill its valence shell, find a way to add seven electrons to its valence shell

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.