I have an acid that is pH 4.33. What is the normality of the acid? SHOW WORK PLEASE

4.68x10⁻⁵N

Explanation:

The pH is defined as -log [H⁺]. If an acid has a pH of 4.33, [H⁺] is:

pH = -log [H⁺]

4.33 =  -log [H⁺]

10^(-4.33) = [H⁺]

4.68x10⁻⁵M = [H⁺]

The [H⁺] is in molarity units, that is mole / L. Normality has as units equivalent / L. As the equivalent in an acid-base reaction is defined as the number of moles of H⁺, in this case:

4.68x10⁻⁵M = 4.68x10⁻⁵N

po-215 i got it right on the quiz