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Chemistry, 27.04.2020 03:11 jhahn001

H2(g) + Br2(g) 5 2 HBr(g)
[H2]=0.10 M [Br2]=0.20 M
Kc = 5.5 x 103
[HBr]=8.5 M
What will happen to the [HBr] as this reaction
approaches equilibrium?

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Answers: 2

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You know the right answer?
H2(g) + Br2(g) 5 2 HBr(g)
[H2]=0.10 M [Br2]=0.20 M
Kc = 5.5 x 103
[HBr]=8.5 M
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