Phosphorus trifluoride is formed from its elements P4 (s) F2 (g) ---> PF3 (g) how many grams of fluorine are needed to react with 6.20 g

This is an incomplete question, here is a complete question.

Phosphorus trifluoride is formed from its elements.

How many grams of fluorine are needed to react with 6.20 g of phosphorus?

Answer : The mass of needed are, 11.4 grams.

Explanation : Given,

Mass of = 6.20 g

Molar mass of = 124 g/mol

Molar mass of = 38 g/mol

First we have to calculate the moles of

Now we have to calculate the moles of

The balanced chemical equation is:

From the balanced reaction we conclude that

As, 1 mole of react with 6 moles of

So, 0.05 moles of react with moles of

Now we have to calculate the mass of

Therefore, the mass of needed are, 11.4 grams.

pure substance: iron,copper

impure substance: water,charcoal

what does the table look like