This reaction involves two successive Michael reactions, and has the following steps: 1. Deprotonation forms enolate ion 1; 2. The first Michael reaction forms enolate ion 2; 3. The second Michael reaction forms enolate ion 3; 4. Protonation leads to the final product. Write the mechanism out on a sheet of paper, and then draw the structure of enolate ion 1.

The structure is on the attached file.

Explanation:

The reaction entails 2 sequencial Michael's reaction with the steps below.

1. Deprotonation forms enolate ion1.

2.The first Michael's reaction results in enolate ion 2.

3.The second Michael's reaction gives enolate ion 3.

4. Protonation leads to the formation of the final product.

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na