In the following reaction, how many grams of nabr will produce 244 grams of nano3? pb(no3)2(aq) + 2 nabr(aq) pbbr2(s) + 2 nano3(aq) the molar mass of nabr is 102.9 grams and that of nano3 is 85 grams.

295.3744 grams of NaBr will produce 244 grams of .

Explanation:

Moles of sodium nitarte=

According to reaction, 2 moles of sodium nitrate is obtained from 2 moles of sodium bromide.

Then 2.8705 mol of sodium nitrate will be obtained from :

of sodium nitrate

Mass of 2.8705 moles of sodium nitrate:

295.3744 grams of NaBr will produce 244 grams of .