If 345.1 g of CO2 are placed in a vessel whose volume is 32.1 L at a temperature of 20.0oC, what will the pressure be? (R= 0.0821 atm*L/mole*K)

5.88atm

Explanation:

First, we obtain the number of mole of CO2 present in the vessel. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the question = 345.1g

Number of mole of CO2 =?

Number of mole = Mass/Molar Mass

Number of mole of CO2 = 345.1/44

= 7.84moles

Now we can easily calculate the pressure by doing the following:

Data obtained from the question include:

V (volume) = 32.1 L

T (temperature) = 20°C = 20 + 273 = 293K

R (gas constant) = 0.0821atm*L/mole*K

n (number of mole) = 7.84moles

P (pressure) =?

We will be making use of the ideal gas equation PV = nRT to calculate the pressure

PV = nRT

P = nRT/V

P = 7.84 x 0.0821 x 293/32.1

P = 5.88atm

Therefore, the pressure is 5.88atm

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