A975-kg sports car (including driver) crosses the rounded top of a hill at determine (a) the normal force exerted by the road on the car, (b) the normal force exerted by the car on the 62.0-kg driver, and (c) the car speed at which the normal force on the driver equals zero

There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill: 
- radius of the hill: 

Solution:

(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car (downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force, , so we can write:
(1)
By rearranging the equation and substituting the numbers, we find N:


(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:


(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:

from which we find

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