A student is asked to prepare 75.0 ml of a 130M solution of HF using a 2.000M standard solution. Calculate the volume in mL of 2.000M HF the student needs to use

Volume required from standard solution = 4675 mL

Explanation:

Given data:

Final volume = 75.0 mL

Final molarity = 130 M

Molarity of standard solution = 2.000 M

Volume required from standard solution = ?

Solution:

We use the formula,

C₁V₁ = C₂V₂

here,

C₁ = Molarity of standard solution

V₁ = Volume required from standard solution

C₂ = Final molarity

V₂ = Final volume

Now we will put the values in formula,

C₁V₁ = C₂V₂

2.000 M × V₁ = 130 M × 75.0 mL

V₁  = 9750 M. mL / 2.000 M

V₁  = 4675 mL

answer; i believe that the correct answer is (a) potassium(k)

the solar system used to have much dust particles option no d