Law of Conservation of Mass Assigned as Homework HQ4.01 In the following chemical reaction between H2 and Cla to produce HCl, what is the sum of the mass of HCl produced plus the mass of left over reactants when 3.36E-1 g of H2 completely reacts with 1.245E+1 g of Cl2? H2(g) + Cl2 (g) → 2HCl(g) T Respond with the correct number of significant figures in scientific notation

The mass of left chlorine gas is 0.497 grams and HCl is 6.13 grams

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of hydrogen gas =

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

Given mass of chlorine gas =

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of hydrogen gas and chlorine gas follows:

By Stoichiometry of the reaction:

1 mole of hydrogen gas reacts with 1 mole of chlorine gas

So, 0.168 moles of hydrogen gas will react with = of chlorine gas

As, given amount of chlorine gas is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrogen gas is considered as a limiting reagent because it limits the formation of product.

Left moles of excess reactant (chlorine gas) = [0.175 - 0.168] = 0.007 moles

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 2 moles of HCl

So, 0.168 moles of hydrogen gas will produce = of HCl

Now, calculating the mass of HCl and chlorine gas from equation 1, we get:

Molar mass of HCl = 36.5 g/mol

Moles of HCl = 0.168 moles

Putting values in equation 1, we get:

Moles of left chlorine gas = 0.007 moles

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

Hence, the mass of left chlorine gas is 0.497 grams and HCl is 6.13 grams

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