Consider the reaction of ethyl acetate with sodium hydroxide: CH3COOC2H5(aq)+NaOH(aq)⇌CH3COONa(aq )+C2H5OH(aq) The reaction is first order in NaOH and second order overall. What is the rate law? View Available Hint(s) Consider the reaction of ethyl acetate with sodium hydroxide: The reaction is first order in and second order overall. What is the rate law? rate=k[CH3COOC2H5]2[NaOH]2 rate=k[CH3COOC2H5][NaOH]2 rate=k[NaOH] rate=k[CH3COOC2H5] rate=k[CH3COOC2H5][NaOH] rate=k[CH3COOC2H5]2[NaOH]

Match the following items. 1. high-intensity bundle of energy being emitted from some decaying nuclei gamma ray 2. particle radiating from the nucleus of some atoms beta particle 3. negative particle identical to an electron but radiating from a decaying nucleus alpha particle

There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .

How are isotopes of the same element alike?