If 6.96 mol of C 5 H 12 reacts with excess O 2 , how many moles of CO 2 will be produced by the following combustion reaction? C 5 H 12 + 8 O 2 ⟶ 6 H 2 O + 5 CO 2 moles of CO 2 : mol

34.8 moles of CO₂ are produced

Explanation:

This is the reaction:

1C₅H₁₂ + 8O₂  →  6H₂O  +  5CO₂

Ratio is 1:5. We make a rule of three

1 mol of pentane can produce 5 moles of CO₂

Then, 6.96 moles of pentane may produce (6.96 .5) / 1 = 34.8 moles

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3